# 如果a+b+c=1000, 且a^2+b^2=c^2(a,b,c为自然数)，如何求出所有a、b、c可能的组合

import time

start_time = time.time()
for a in range(0, 1001):
    for b in range(0, 1001):
        for c in range(0, 1001):
            if a + b + c == 1000 and a ** 2 + b ** 2 == c ** 2:
                print(f"a,b,c:{a},{b},{c}")
end_time = time.time()
print(f"times:{end_time - start_time}")
